Solve (sqrt{1-0,19}+0,3^2-6/25)*(-3)

$$( \sqrt { 1 - 0,19 } + 0,3 ^ { 2 } - \frac { 6 } { 25 } ) \cdot ( - 3 )$$

Evaluate

$$-1,98$$

Solution Steps

Subtract 0,19 from 1 to get 0,81.

$$\left(\sqrt{0,81}+0\times 3^{2}-\frac{6}{25}\right)\left(-3\right)$$

Calculate the square root of 0,81 and get 0,9.

$$\left(0,9+0\times 3^{2}-\frac{6}{25}\right)\left(-3\right)$$

Calculate 3 to the power of 2 and get 9.

$$\left(0,9+0\times 9-\frac{6}{25}\right)\left(-3\right)$$

Multiply 0 and 9 to get 0.

$$\left(0,9+0-\frac{6}{25}\right)\left(-3\right)$$

Add 0,9 and 0 to get 0,9.

$$\left(0,9-\frac{6}{25}\right)\left(-3\right)$$

Convert decimal number 0,9 to fraction \frac{9}{10}.

$$\left(\frac{9}{10}-\frac{6}{25}\right)\left(-3\right)$$

Least common multiple of 10 and 25 is 50. Convert \frac{9}{10} and \frac{6}{25} to fractions with denominator 50.

$$\left(\frac{45}{50}-\frac{12}{50}\right)\left(-3\right)$$

Since \frac{45}{50} and \frac{12}{50} have the same denominator, subtract them by subtracting their numerators.

$$\frac{45-12}{50}\left(-3\right)$$

Subtract 12 from 45 to get 33.

$$\frac{33}{50}\left(-3\right)$$

Express \frac{33}{50}\left(-3\right) as a single fraction.

$$\frac{33\left(-3\right)}{50}$$

Multiply 33 and -3 to get -99.

$$\frac{-99}{50}$$

Fraction \frac{-99}{50} can be rewritten as -\frac{99}{50} by extracting the negative sign.

$$-\frac{99}{50}$$

Factor

$$-1,98$$