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\left(3i+i\right)\left(5-6i\right)
Calculate the square root of -9 and get 3i.
4i\left(5-6i\right)
Add 3i and i to get 4i.
4i\times 5+4\left(-6\right)i^{2}
Multiply 4i times 5-6i.
4i\times 5+4\left(-6\right)\left(-1\right)
By definition, i^{2} is -1.
24+20i
Do the multiplications. Reorder the terms.
Re(\left(3i+i\right)\left(5-6i\right))
Calculate the square root of -9 and get 3i.
Re(4i\left(5-6i\right))
Add 3i and i to get 4i.
Re(4i\times 5+4\left(-6\right)i^{2})
Multiply 4i times 5-6i.
Re(4i\times 5+4\left(-6\right)\left(-1\right))
By definition, i^{2} is -1.
Re(24+20i)
Do the multiplications in 4i\times 5+4\left(-6\right)\left(-1\right). Reorder the terms.
24
The real part of 24+20i is 24.