Solve (sqrt{2^2-3/2(3)+3}+10/6)^2=P

$$( \sqrt { \frac { 2 ^ { 2 } - 3 } { 2 ( 3 ) + 3 } } + \frac { 10 } { 6 } ) ^ { 2 } = P$$

Solve for P

$$P=4$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$\left(\sqrt{\frac{4-3}{2\times 3+3}}+\frac{10}{6}\right)^{2}=P$$

Subtract 3 from 4 to get 1.

$$\left(\sqrt{\frac{1}{2\times 3+3}}+\frac{10}{6}\right)^{2}=P$$

Multiply 2 and 3 to get 6.

$$\left(\sqrt{\frac{1}{6+3}}+\frac{10}{6}\right)^{2}=P$$

Add 6 and 3 to get 9.

$$\left(\sqrt{\frac{1}{9}}+\frac{10}{6}\right)^{2}=P$$

Rewrite the square root of the division \frac{1}{9} as the division of square roots \frac{\sqrt{1}}{\sqrt{9}}. Take the square root of both numerator and denominator.

$$\left(\frac{1}{3}+\frac{10}{6}\right)^{2}=P$$

Reduce the fraction \frac{10}{6} to lowest terms by extracting and canceling out 2.

$$\left(\frac{1}{3}+\frac{5}{3}\right)^{2}=P$$

Add \frac{1}{3} and \frac{5}{3} to get 2.

$$2^{2}=P$$

Calculate 2 to the power of 2 and get 4.

$$4=P$$

Swap sides so that all variable terms are on the left hand side.

$$P=4$$