Solve (sqrt{1/9}-[(1/3)^2:(1/2)^2*15-(05+22/3)+05]^3+frac{2}{3})

$$( \sqrt { \frac { 1 } { 9 } } - [ ( \frac { 1 } { 3 } ) ^ { 2 } : ( \frac { 1 } { 2 } ) ^ { 2 } \times 15 - ( 05 + 2 \frac { 2 } { 3 } ) + 05 ] ^ { 3 } + \frac { 2 } { 3 } )$$

Evaluate

$$-63$$

Solution Steps

Rewrite the square root of the division \frac{1}{9} as the division of square roots \frac{\sqrt{1}}{\sqrt{9}}. Take the square root of both numerator and denominator.

$$\frac{1}{3}-\left(\frac{\left(\frac{1}{3}\right)^{2}}{\left(\frac{1}{2}\right)^{2}}\times 15-\left(0\times 5+\frac{2\times 3+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{1}{3}-\left(\frac{\frac{1}{9}}{\left(\frac{1}{2}\right)^{2}}\times 15-\left(0\times 5+\frac{2\times 3+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{3}-\left(\frac{\frac{1}{9}}{\frac{1}{4}}\times 15-\left(0\times 5+\frac{2\times 3+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Divide \frac{1}{9} by \frac{1}{4} by multiplying \frac{1}{9} by the reciprocal of \frac{1}{4}.

$$\frac{1}{3}-\left(\frac{1}{9}\times 4\times 15-\left(0\times 5+\frac{2\times 3+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Multiply \frac{1}{9} and 4 to get \frac{4}{9}.

$$\frac{1}{3}-\left(\frac{4}{9}\times 15-\left(0\times 5+\frac{2\times 3+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Multiply \frac{4}{9} and 15 to get \frac{20}{3}.

$$\frac{1}{3}-\left(\frac{20}{3}-\left(0\times 5+\frac{2\times 3+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Multiply 0 and 5 to get 0.

$$\frac{1}{3}-\left(\frac{20}{3}-\left(0+\frac{2\times 3+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{1}{3}-\left(\frac{20}{3}-\left(0+\frac{6+2}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Add 6 and 2 to get 8.

$$\frac{1}{3}-\left(\frac{20}{3}-\left(0+\frac{8}{3}\right)+0\times 5\right)^{3}+\frac{2}{3}$$

Add 0 and \frac{8}{3} to get \frac{8}{3}.

$$\frac{1}{3}-\left(\frac{20}{3}-\frac{8}{3}+0\times 5\right)^{3}+\frac{2}{3}$$

Subtract \frac{8}{3} from \frac{20}{3} to get 4.

$$\frac{1}{3}-\left(4+0\times 5\right)^{3}+\frac{2}{3}$$

Multiply 0 and 5 to get 0.

$$\frac{1}{3}-\left(4+0\right)^{3}+\frac{2}{3}$$

Add 4 and 0 to get 4.

$$\frac{1}{3}-4^{3}+\frac{2}{3}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{1}{3}-64+\frac{2}{3}$$

Subtract 64 from \frac{1}{3} to get -\frac{191}{3}.

$$-\frac{191}{3}+\frac{2}{3}$$

Add -\frac{191}{3} and \frac{2}{3} to get -63.

$$-63$$

Factor

$$-63$$