Solve (sin(pi)+3sin(pi/2))div(cos(pi)+2cos(pidiv2))

$$( \sin ( \pi ) +3 \sin ( \frac{ \pi }{ 2 } ) ) \div ( \cos ( \pi ) +2 \cos ( \pi \div 2 ) )$$

Evaluate

$$-3$$

Solution Steps

Get the value of \sin(\pi ) from trigonometric values table.

$$\frac{0+3\sin(\frac{\pi }{2})}{\cos(\pi )+2\cos(\frac{\pi }{2})}$$

Get the value of \sin(\frac{\pi }{2}) from trigonometric values table.

$$\frac{0+3\times 1}{\cos(\pi )+2\cos(\frac{\pi }{2})}$$

Multiply 3 and 1 to get 3.

$$\frac{0+3}{\cos(\pi )+2\cos(\frac{\pi }{2})}$$

Add 0 and 3 to get 3.

$$\frac{3}{\cos(\pi )+2\cos(\frac{\pi }{2})}$$

Get the value of \cos(\pi ) from trigonometric values table.

$$\frac{3}{-1+2\cos(\frac{\pi }{2})}$$

Get the value of \cos(\frac{\pi }{2}) from trigonometric values table.

$$\frac{3}{-1+2\times 0}$$

Multiply 2 and 0 to get 0.

$$\frac{3}{-1+0}$$

Add -1 and 0 to get -1.

$$\frac{3}{-1}$$

Fraction \frac{3}{-1} can be rewritten as -3 by extracting the negative sign.

$$-3$$

Factor

$$-3$$