Solve (pi-2)^0+sqrt{4}+(-1)^2019-(1/2)

$$( \pi - 2 ) ^ { 0 } + \sqrt { 4 } + ( - 1 ) ^ { 2019 } - ( \frac { 1 } { 2 } )$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Calculate \pi -2 to the power of 0 and get 1.

$$1+\sqrt{4}+\left(-1\right)^{2019}-\frac{1}{2}$$

Calculate the square root of 4 and get 2.

$$1+2+\left(-1\right)^{2019}-\frac{1}{2}$$

Add 1 and 2 to get 3.

$$3+\left(-1\right)^{2019}-\frac{1}{2}$$

Calculate -1 to the power of 2019 and get -1.

$$3-1-\frac{1}{2}$$

Subtract 1 from 3 to get 2.

$$2-\frac{1}{2}$$

Subtract \frac{1}{2} from 2 to get \frac{3}{2}.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$