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\left(3-\log_{2}\left(128\right)\right)\log_{\frac{1}{3}}\left(81\right)
The base 5 logarithm of 125 is 3.
\left(3-7\right)\log_{\frac{1}{3}}\left(81\right)
The base 2 logarithm of 128 is 7.
-4\log_{\frac{1}{3}}\left(81\right)
Subtract 7 from 3 to get -4.
-4\left(-4\right)
The base \frac{1}{3} logarithm of 81 is -4.
16
Multiply -4 and -4 to get 16.