Solve (left(268-200left(1-xright)right)115geq9200

$$( \left( 268-200 \left( 1-x \right) \right) 115 \geq 9200$$

Solve for x

$$x\geq \frac{3}{50}$$

Solution Steps

Divide both sides by 115. Since 115 is positive, the inequality direction remains the same.

$$268-200\left(1-x\right)\geq \frac{9200}{115}$$

Divide 9200 by 115 to get 80.

$$268-200\left(1-x\right)\geq 80$$

Use the distributive property to multiply -200 by 1-x.

$$268-200+200x\geq 80$$

Subtract 200 from 268 to get 68.

$$68+200x\geq 80$$

Subtract 68 from both sides.

$$200x\geq 80-68$$

Subtract 68 from 80 to get 12.

$$200x\geq 12$$

Divide both sides by 200. Since 200 is positive, the inequality direction remains the same.

$$x\geq \frac{12}{200}$$

Reduce the fraction \frac{12}{200} to lowest terms by extracting and canceling out 4.

$$x\geq \frac{3}{50}$$