Solve (9/8*20/2-8/10)+3/12

$$( \frac{ 9 }{ 8 } \times \frac{ 20 }{ 2 } - \frac{ 8 }{ 10 } )+ \frac{ 3 }{ 12 }$$

Evaluate

$$\frac{107}{10}=10.7$$

Solution Steps

Divide 20 by 2 to get 10.

$$\frac{9}{8}\times 10-\frac{8}{10}+\frac{3}{12}$$

Express \frac{9}{8}\times 10 as a single fraction.

$$\frac{9\times 10}{8}-\frac{8}{10}+\frac{3}{12}$$

Multiply 9 and 10 to get 90.

$$\frac{90}{8}-\frac{8}{10}+\frac{3}{12}$$

Reduce the fraction \frac{90}{8} to lowest terms by extracting and canceling out 2.

$$\frac{45}{4}-\frac{8}{10}+\frac{3}{12}$$

Reduce the fraction \frac{8}{10} to lowest terms by extracting and canceling out 2.

$$\frac{45}{4}-\frac{4}{5}+\frac{3}{12}$$

Least common multiple of 4 and 5 is 20. Convert \frac{45}{4} and \frac{4}{5} to fractions with denominator 20.

$$\frac{225}{20}-\frac{16}{20}+\frac{3}{12}$$

Since \frac{225}{20} and \frac{16}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{225-16}{20}+\frac{3}{12}$$

Subtract 16 from 225 to get 209.

$$\frac{209}{20}+\frac{3}{12}$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\frac{209}{20}+\frac{1}{4}$$

Least common multiple of 20 and 4 is 20. Convert \frac{209}{20} and \frac{1}{4} to fractions with denominator 20.

$$\frac{209}{20}+\frac{5}{20}$$

Since \frac{209}{20} and \frac{5}{20} have the same denominator, add them by adding their numerators.

$$\frac{209+5}{20}$$

Add 209 and 5 to get 214.

$$\frac{214}{20}$$

Reduce the fraction \frac{214}{20} to lowest terms by extracting and canceling out 2.

$$\frac{107}{10}$$

Factor

$$\frac{107}{2 \cdot 5} = 10\frac{7}{10} = 10.7$$