Solve (8/9-3^2x)*67=49

$$( \frac{ 8 }{ 9 } - { 3 }^{ 2 } x) \times 67=49$$

Solve for x

$$x=\frac{95}{5427}\approx 0.017505067$$

Steps for Solving Linear Equation

Divide both sides by 67.

$$\frac{8}{9}-3^{2}x=\frac{49}{67}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{8}{9}-9x=\frac{49}{67}$$

Subtract \frac{8}{9} from both sides.

$$-9x=\frac{49}{67}-\frac{8}{9}$$

Least common multiple of 67 and 9 is 603. Convert \frac{49}{67} and \frac{8}{9} to fractions with denominator 603.

$$-9x=\frac{441}{603}-\frac{536}{603}$$

Since \frac{441}{603} and \frac{536}{603} have the same denominator, subtract them by subtracting their numerators.

$$-9x=\frac{441-536}{603}$$

Subtract 536 from 441 to get -95.

$$-9x=-\frac{95}{603}$$

Divide both sides by -9.

$$x=\frac{-\frac{95}{603}}{-9}$$

Express \frac{-\frac{95}{603}}{-9} as a single fraction.

$$x=\frac{-95}{603\left(-9\right)}$$

Multiply 603 and -9 to get -5427.

$$x=\frac{-95}{-5427}$$

Fraction \frac{-95}{-5427} can be simplified to \frac{95}{5427} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{95}{5427}$$