Solve (8/3-8)-(-8/3+8)

$$( \frac{ 8 }{ 3 } -8)-(- \frac{ 8 }{ 3 } +8)$$

Evaluate

$$-\frac{32}{3}\approx -10.666666667$$

Solution Steps

Convert 8 to fraction \frac{24}{3}.

$$\frac{8}{3}-\frac{24}{3}-\left(-\frac{8}{3}+8\right)$$

Since \frac{8}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-24}{3}-\left(-\frac{8}{3}+8\right)$$

Subtract 24 from 8 to get -16.

$$-\frac{16}{3}-\left(-\frac{8}{3}+8\right)$$

Convert 8 to fraction \frac{24}{3}.

$$-\frac{16}{3}-\left(-\frac{8}{3}+\frac{24}{3}\right)$$

Since -\frac{8}{3} and \frac{24}{3} have the same denominator, add them by adding their numerators.

$$-\frac{16}{3}-\frac{-8+24}{3}$$

Add -8 and 24 to get 16.

$$-\frac{16}{3}-\frac{16}{3}$$

Since -\frac{16}{3} and \frac{16}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-16-16}{3}$$

Subtract 16 from -16 to get -32.

$$-\frac{32}{3}$$

Factor

$$-\frac{32}{3} = -10\frac{2}{3} = -10.666666666666666$$