Solve (8/3)-4-20/9

$$( \frac{ 8 }{ 3 } )-4- \frac{ 20 }{ 9 }$$

Evaluate

$$-\frac{32}{9}\approx -3.555555556$$

Solution Steps

Convert 4 to fraction \frac{12}{3}.

$$\frac{8}{3}-\frac{12}{3}-\frac{20}{9}$$

Since \frac{8}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-12}{3}-\frac{20}{9}$$

Subtract 12 from 8 to get -4.

$$-\frac{4}{3}-\frac{20}{9}$$

Least common multiple of 3 and 9 is 9. Convert -\frac{4}{3} and \frac{20}{9} to fractions with denominator 9.

$$-\frac{12}{9}-\frac{20}{9}$$

Since -\frac{12}{9} and \frac{20}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-12-20}{9}$$

Subtract 20 from -12 to get -32.

$$-\frac{32}{9}$$

Factor

$$-\frac{32}{9} = -3\frac{5}{9} = -3.5555555555555554$$