Solve (7910/6850-1)*x=112

$$( \frac{ 7910 }{ 6850 } -1) \times x=112$$

Solve for x

$$x = \frac{38360}{53} = 723\frac{41}{53} \approx 723.773584906$$

Steps for Solving Linear Equation

Reduce the fraction \frac{7910}{6850} to lowest terms by extracting and canceling out 10.

$$\left(\frac{791}{685}-1\right)x=112$$

Convert 1 to fraction \frac{685}{685}.

$$\left(\frac{791}{685}-\frac{685}{685}\right)x=112$$

Since \frac{791}{685} and \frac{685}{685} have the same denominator, subtract them by subtracting their numerators.

$$\frac{791-685}{685}x=112$$

Subtract 685 from 791 to get 106.

$$\frac{106}{685}x=112$$

Multiply both sides by \frac{685}{106}, the reciprocal of \frac{106}{685}.

$$x=112\times \frac{685}{106}$$

Express 112\times \frac{685}{106} as a single fraction.

$$x=\frac{112\times 685}{106}$$

Multiply 112 and 685 to get 76720.

$$x=\frac{76720}{106}$$

Reduce the fraction \frac{76720}{106} to lowest terms by extracting and canceling out 2.

$$x=\frac{38360}{53}$$