Solve (7/22+14/11)div10/33

$$( \frac{ 7 }{ 22 } + \frac{ 14 }{ 11 } ) \div \frac{ 10 }{ 33 }$$

Evaluate

$$\frac{21}{4}=5.25$$

Solution Steps

Least common multiple of 22 and 11 is 22. Convert \frac{7}{22} and \frac{14}{11} to fractions with denominator 22.

$$\frac{\frac{7}{22}+\frac{28}{22}}{\frac{10}{33}}$$

Since \frac{7}{22} and \frac{28}{22} have the same denominator, add them by adding their numerators.

$$\frac{\frac{7+28}{22}}{\frac{10}{33}}$$

Add 7 and 28 to get 35.

$$\frac{\frac{35}{22}}{\frac{10}{33}}$$

Divide \frac{35}{22} by \frac{10}{33} by multiplying \frac{35}{22} by the reciprocal of \frac{10}{33}.

$$\frac{35}{22}\times \frac{33}{10}$$

Multiply \frac{35}{22} times \frac{33}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{35\times 33}{22\times 10}$$

Do the multiplications in the fraction \frac{35\times 33}{22\times 10}.

$$\frac{1155}{220}$$

Reduce the fraction \frac{1155}{220} to lowest terms by extracting and canceling out 55.

$$\frac{21}{4}$$

Factor

$$\frac{3 \cdot 7}{2 ^ {2}} = 5\frac{1}{4} = 5.25$$