Solve (5/7+3/28)div32/7

$$( \frac{ 5 }{ 7 } + \frac{ 3 }{ 28 } ) \div 3 \frac{ 2 }{ 7 }$$

Evaluate

$$\frac{1}{4}=0.25$$

Solution Steps

Least common multiple of 7 and 28 is 28. Convert \frac{5}{7} and \frac{3}{28} to fractions with denominator 28.

$$\frac{\frac{20}{28}+\frac{3}{28}}{\frac{3\times 7+2}{7}}$$

Since \frac{20}{28} and \frac{3}{28} have the same denominator, add them by adding their numerators.

$$\frac{\frac{20+3}{28}}{\frac{3\times 7+2}{7}}$$

Add 20 and 3 to get 23.

$$\frac{\frac{23}{28}}{\frac{3\times 7+2}{7}}$$

Multiply 3 and 7 to get 21.

$$\frac{\frac{23}{28}}{\frac{21+2}{7}}$$

Add 21 and 2 to get 23.

$$\frac{\frac{23}{28}}{\frac{23}{7}}$$

Divide \frac{23}{28} by \frac{23}{7} by multiplying \frac{23}{28} by the reciprocal of \frac{23}{7}.

$$\frac{23}{28}\times \frac{7}{23}$$

Multiply \frac{23}{28} times \frac{7}{23} by multiplying numerator times numerator and denominator times denominator.

$$\frac{23\times 7}{28\times 23}$$

Cancel out 23 in both numerator and denominator.

$$\frac{7}{28}$$

Reduce the fraction \frac{7}{28} to lowest terms by extracting and canceling out 7.

$$\frac{1}{4}$$

Factor

$$\frac{1}{2 ^ {2}} = 0.25$$