Solve (41*13/28)+(18*13/27)

$$( \frac{ 41 \times 13 }{ 28 } )+( \frac{ 18 \times 13 }{ 27 } )$$

Evaluate

$$\frac{2327}{84}\approx 27.702380952$$

Solution Steps

Multiply 41 and 13 to get 533.

$$\frac{533}{28}+\frac{18\times 13}{27}$$

Multiply 18 and 13 to get 234.

$$\frac{533}{28}+\frac{234}{27}$$

Reduce the fraction \frac{234}{27} to lowest terms by extracting and canceling out 9.

$$\frac{533}{28}+\frac{26}{3}$$

Least common multiple of 28 and 3 is 84. Convert \frac{533}{28} and \frac{26}{3} to fractions with denominator 84.

$$\frac{1599}{84}+\frac{728}{84}$$

Since \frac{1599}{84} and \frac{728}{84} have the same denominator, add them by adding their numerators.

$$\frac{1599+728}{84}$$

Add 1599 and 728 to get 2327.

$$\frac{2327}{84}$$

Factor

$$\frac{13 \cdot 179}{2 ^ {2} \cdot 3 \cdot 7} = 27\frac{59}{84} = 27.702380952380953$$