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\frac{\frac{4}{x}+\frac{\left(3-x\right)x}{x}}{x-\frac{1}{x}}
To add or subtract expressions, expand them to make their denominators the same. Multiply 3-x times \frac{x}{x}.
\frac{\frac{4+\left(3-x\right)x}{x}}{x-\frac{1}{x}}
Since \frac{4}{x} and \frac{\left(3-x\right)x}{x} have the same denominator, add them by adding their numerators.
\frac{\frac{4+3x-x^{2}}{x}}{x-\frac{1}{x}}
Do the multiplications in 4+\left(3-x\right)x.
\frac{\frac{4+3x-x^{2}}{x}}{\frac{xx}{x}-\frac{1}{x}}
To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x}{x}.
\frac{\frac{4+3x-x^{2}}{x}}{\frac{xx-1}{x}}
Since \frac{xx}{x} and \frac{1}{x} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{4+3x-x^{2}}{x}}{\frac{x^{2}-1}{x}}
Do the multiplications in xx-1.
\frac{\left(4+3x-x^{2}\right)x}{x\left(x^{2}-1\right)}
Divide \frac{4+3x-x^{2}}{x} by \frac{x^{2}-1}{x} by multiplying \frac{4+3x-x^{2}}{x} by the reciprocal of \frac{x^{2}-1}{x}.
\frac{-x^{2}+3x+4}{x^{2}-1}
Cancel out x in both numerator and denominator.
\frac{\left(x-4\right)\left(-x-1\right)}{\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored.
\frac{-\left(x-4\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}
Extract the negative sign in -1-x.
\frac{-\left(x-4\right)}{x-1}
Cancel out x+1 in both numerator and denominator.
\frac{-x+4}{x-1}
Expand the expression.
\frac{\frac{4}{x}+\frac{\left(3-x\right)x}{x}}{x-\frac{1}{x}}
To add or subtract expressions, expand them to make their denominators the same. Multiply 3-x times \frac{x}{x}.
\frac{\frac{4+\left(3-x\right)x}{x}}{x-\frac{1}{x}}
Since \frac{4}{x} and \frac{\left(3-x\right)x}{x} have the same denominator, add them by adding their numerators.
\frac{\frac{4+3x-x^{2}}{x}}{x-\frac{1}{x}}
Do the multiplications in 4+\left(3-x\right)x.
\frac{\frac{4+3x-x^{2}}{x}}{\frac{xx}{x}-\frac{1}{x}}
To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x}{x}.
\frac{\frac{4+3x-x^{2}}{x}}{\frac{xx-1}{x}}
Since \frac{xx}{x} and \frac{1}{x} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{4+3x-x^{2}}{x}}{\frac{x^{2}-1}{x}}
Do the multiplications in xx-1.
\frac{\left(4+3x-x^{2}\right)x}{x\left(x^{2}-1\right)}
Divide \frac{4+3x-x^{2}}{x} by \frac{x^{2}-1}{x} by multiplying \frac{4+3x-x^{2}}{x} by the reciprocal of \frac{x^{2}-1}{x}.
\frac{-x^{2}+3x+4}{x^{2}-1}
Cancel out x in both numerator and denominator.
\frac{\left(x-4\right)\left(-x-1\right)}{\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored.
\frac{-\left(x-4\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}
Extract the negative sign in -1-x.
\frac{-\left(x-4\right)}{x-1}
Cancel out x+1 in both numerator and denominator.
\frac{-x+4}{x-1}
Expand the expression.