Solve (3/5*31/2+3)*-30

$$( \frac{ 3 }{ 5 } \times \frac{ 31 }{ 2 } +3) \times -30$$

Evaluate

$$-369$$

Solution Steps

Multiply \frac{3}{5} times \frac{31}{2} by multiplying numerator times numerator and denominator times denominator.

$$\left(\frac{3\times 31}{5\times 2}+3\right)\left(-30\right)$$

Do the multiplications in the fraction \frac{3\times 31}{5\times 2}.

$$\left(\frac{93}{10}+3\right)\left(-30\right)$$

Convert 3 to fraction \frac{30}{10}.

$$\left(\frac{93}{10}+\frac{30}{10}\right)\left(-30\right)$$

Since \frac{93}{10} and \frac{30}{10} have the same denominator, add them by adding their numerators.

$$\frac{93+30}{10}\left(-30\right)$$

Add 93 and 30 to get 123.

$$\frac{123}{10}\left(-30\right)$$

Express \frac{123}{10}\left(-30\right) as a single fraction.

$$\frac{123\left(-30\right)}{10}$$

Multiply 123 and -30 to get -3690.

$$\frac{-3690}{10}$$

Divide -3690 by 10 to get -369.

$$-369$$

Factor

$$-369$$