Solve (3/4+23/8)*258

$$( \frac{ 3 }{ 4 } + 2 \frac { 3 } { 8 } ) \times 258$$

Evaluate

$$\frac{3225}{4}=806.25$$

Solution Steps

Multiply 2 and 8 to get 16.

$$\left(\frac{3}{4}+\frac{16+3}{8}\right)\times 258$$

Add 16 and 3 to get 19.

$$\left(\frac{3}{4}+\frac{19}{8}\right)\times 258$$

Least common multiple of 4 and 8 is 8. Convert \frac{3}{4} and \frac{19}{8} to fractions with denominator 8.

$$\left(\frac{6}{8}+\frac{19}{8}\right)\times 258$$

Since \frac{6}{8} and \frac{19}{8} have the same denominator, add them by adding their numerators.

$$\frac{6+19}{8}\times 258$$

Add 6 and 19 to get 25.

$$\frac{25}{8}\times 258$$

Express \frac{25}{8}\times 258 as a single fraction.

$$\frac{25\times 258}{8}$$

Multiply 25 and 258 to get 6450.

$$\frac{6450}{8}$$

Reduce the fraction \frac{6450}{8} to lowest terms by extracting and canceling out 2.

$$\frac{3225}{4}$$

Factor

$$\frac{3 \cdot 5 ^ {2} \cdot 43}{2 ^ {2}} = 806\frac{1}{4} = 806.25$$