Solve (3/2-2)*(-1+4i)

$$( \frac{ 3 }{ 2 } -2) \times (-1+4i)$$

Evaluate

$$\frac{1}{2}-2i=0.5-2i$$

Solution Steps

Convert 2 to fraction \frac{4}{2}.

$$\left(\frac{3}{2}-\frac{4}{2}\right)\left(-1+4i\right)$$

Since \frac{3}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-4}{2}\left(-1+4i\right)$$

Subtract 4 from 3 to get -1.

$$-\frac{1}{2}\left(-1+4i\right)$$

Multiply -\frac{1}{2} times -1+4i.

$$-\frac{1}{2}\left(-1\right)-\frac{1}{2}\times \left(4i\right)$$

Do the multiplications.

$$\frac{1}{2}-2i$$

Real Part

$$\frac{1}{2} = 0.5$$

Solution Steps

Convert 2 to fraction \frac{4}{2}.

$$Re(\left(\frac{3}{2}-\frac{4}{2}\right)\left(-1+4i\right))$$

Since \frac{3}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$Re(\frac{3-4}{2}\left(-1+4i\right))$$

Subtract 4 from 3 to get -1.

$$Re(-\frac{1}{2}\left(-1+4i\right))$$

Multiply -\frac{1}{2} times -1+4i.

$$Re(-\frac{1}{2}\left(-1\right)-\frac{1}{2}\times \left(4i\right))$$

Do the multiplications in -\frac{1}{2}\left(-1\right)-\frac{1}{2}\times \left(4i\right).

$$Re(\frac{1}{2}-2i)$$

The real part of \frac{1}{2}-2i is \frac{1}{2}.

$$\frac{1}{2}$$