Solve (2x+3/x4)=5

$$( \frac{ 2x+3 }{ x4 } )=5$$

Solve for x

$$x=\frac{5x_{4}-3}{2}$$

$$x_{4}\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by x_{4}.

$$2x+3=5x_{4}$$

Subtract 3 from both sides.

$$2x=5x_{4}-3$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{5x_{4}-3}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{5x_{4}-3}{2}$$

Solve for x_4

$$x_{4}=\frac{2x+3}{5}$$

$$x\neq -\frac{3}{2}$$

Steps for Solving Linear Equation

Variable x_{4} cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x_{4}.

$$2x+3=5x_{4}$$

Swap sides so that all variable terms are on the left hand side.

$$5x_{4}=2x+3$$

Divide both sides by 5.

$$\frac{5x_{4}}{5}=\frac{2x+3}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x_{4}=\frac{2x+3}{5}$$

Variable x_{4} cannot be equal to 0.

$$x_{4}=\frac{2x+3}{5}\text{, }x_{4}\neq 0$$