Solve (28+245+x/48+50+48+52)*01+8/10*015+15/30*075>05

$$( \frac{ 28+245+x }{ 48+50+48+52 } ) \times 01+ \frac{ 8 }{ 10 } \times 015+ \frac{ 15 }{ 30 } \times 075 > 05$$

Evaluate (complex solution)

Solution Steps

Add 28 and 245 to get 273.

$$\frac{273+x}{48+50+48+52}\times 0\times 1+\frac{8}{10}\times 0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Add 48 and 50 to get 98.

$$\frac{273+x}{98+48+52}\times 0\times 1+\frac{8}{10}\times 0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Add 98 and 48 to get 146.

$$\frac{273+x}{146+52}\times 0\times 1+\frac{8}{10}\times 0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Add 146 and 52 to get 198.

$$\frac{273+x}{198}\times 0\times 1+\frac{8}{10}\times 0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Multiply 0 and 1 to get 0.

$$\frac{273+x}{198}\times 0+\frac{8}{10}\times 0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Anything times zero gives zero.

$$0+\frac{8}{10}\times 0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Reduce the fraction \frac{8}{10} to lowest terms by extracting and canceling out 2.

$$0+\frac{4}{5}\times 0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Multiply \frac{4}{5} and 0 to get 0.

$$0+0\times 15+\frac{15}{30}\times 0\times 75>0\times 5$$

Multiply 0 and 15 to get 0.

$$0+0+\frac{15}{30}\times 0\times 75>0\times 5$$

Add 0 and 0 to get 0.

$$\frac{15}{30}\times 0\times 75>0\times 5$$

Reduce the fraction \frac{15}{30} to lowest terms by extracting and canceling out 15.

$$\frac{1}{2}\times 0\times 75>0\times 5$$

Multiply \frac{1}{2} and 0 to get 0.

$$0\times 75>0\times 5$$

Multiply 0 and 75 to get 0.

$$0>0\times 5$$

Multiply 0 and 5 to get 0.

$$0>0$$

Compare 0 and 0.

$$\text{false}$$