Solve (2/9+5/18)div1/9=

$$( \frac{ 2 }{ 9 } + \frac{ 5 }{ 18 } ) \div \frac{ 1 }{ 9 } =$$

Evaluate

$$\frac{9}{2}=4.5$$

Solution Steps

Least common multiple of 9 and 18 is 18. Convert \frac{2}{9} and \frac{5}{18} to fractions with denominator 18.

$$\frac{\frac{4}{18}+\frac{5}{18}}{\frac{1}{9}}$$

Since \frac{4}{18} and \frac{5}{18} have the same denominator, add them by adding their numerators.

$$\frac{\frac{4+5}{18}}{\frac{1}{9}}$$

Add 4 and 5 to get 9.

$$\frac{\frac{9}{18}}{\frac{1}{9}}$$

Reduce the fraction \frac{9}{18} to lowest terms by extracting and canceling out 9.

$$\frac{\frac{1}{2}}{\frac{1}{9}}$$

Divide \frac{1}{2} by \frac{1}{9} by multiplying \frac{1}{2} by the reciprocal of \frac{1}{9}.

$$\frac{1}{2}\times 9$$

Multiply \frac{1}{2} and 9 to get \frac{9}{2}.

$$\frac{9}{2}$$

Factor

$$\frac{3 ^ {2}}{2} = 4\frac{1}{2} = 4.5$$