Solve (2/7+3/10+3/8)div3

$$( \frac{ 2 }{ 7 } + \frac{ 3 }{ 10 } + \frac{ 3 }{ 8 } ) \div 3$$

Evaluate

$$\frac{269}{840}\approx 0.320238095$$

Solution Steps

Least common multiple of 7 and 10 is 70. Convert \frac{2}{7} and \frac{3}{10} to fractions with denominator 70.

$$\frac{\frac{20}{70}+\frac{21}{70}+\frac{3}{8}}{3}$$

Since \frac{20}{70} and \frac{21}{70} have the same denominator, add them by adding their numerators.

$$\frac{\frac{20+21}{70}+\frac{3}{8}}{3}$$

Add 20 and 21 to get 41.

$$\frac{\frac{41}{70}+\frac{3}{8}}{3}$$

Least common multiple of 70 and 8 is 280. Convert \frac{41}{70} and \frac{3}{8} to fractions with denominator 280.

$$\frac{\frac{164}{280}+\frac{105}{280}}{3}$$

Since \frac{164}{280} and \frac{105}{280} have the same denominator, add them by adding their numerators.

$$\frac{\frac{164+105}{280}}{3}$$

Add 164 and 105 to get 269.

$$\frac{\frac{269}{280}}{3}$$

Express \frac{\frac{269}{280}}{3} as a single fraction.

$$\frac{269}{280\times 3}$$

Multiply 280 and 3 to get 840.

$$\frac{269}{840}$$

Factor

$$\frac{269}{2 ^ {3} \cdot 3 \cdot 5 \cdot 7} = 0.3202380952380952$$