Solve (2/3-4/9)*3/8

$$( \frac{ 2 }{ 3 } - \frac{ 4 }{ 9 } ) \times \frac{ 3 }{ 8 }$$

Evaluate

$$\frac{1}{12}\approx 0.083333333$$

Solution Steps

Least common multiple of 3 and 9 is 9. Convert \frac{2}{3} and \frac{4}{9} to fractions with denominator 9.

$$\left(\frac{6}{9}-\frac{4}{9}\right)\times \frac{3}{8}$$

Since \frac{6}{9} and \frac{4}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-4}{9}\times \frac{3}{8}$$

Subtract 4 from 6 to get 2.

$$\frac{2}{9}\times \frac{3}{8}$$

Multiply \frac{2}{9} times \frac{3}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 3}{9\times 8}$$

Do the multiplications in the fraction \frac{2\times 3}{9\times 8}.

$$\frac{6}{72}$$

Reduce the fraction \frac{6}{72} to lowest terms by extracting and canceling out 6.

$$\frac{1}{12}$$

Factor

$$\frac{1}{2 ^ {2} \cdot 3} = 0.08333333333333333$$