Solve (2/3-1/5)div(-1/15)=

$$( \frac{ 2 }{ 3 } - \frac{ 1 }{ 5 } ) \div (- \frac{ 1 }{ 15 } )=$$

Evaluate

$$-7$$

Solution Steps

Least common multiple of 3 and 5 is 15. Convert \frac{2}{3} and \frac{1}{5} to fractions with denominator 15.

$$\frac{\frac{10}{15}-\frac{3}{15}}{-\frac{1}{15}}$$

Since \frac{10}{15} and \frac{3}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{10-3}{15}}{-\frac{1}{15}}$$

Subtract 3 from 10 to get 7.

$$\frac{\frac{7}{15}}{-\frac{1}{15}}$$

Divide \frac{7}{15} by -\frac{1}{15} by multiplying \frac{7}{15} by the reciprocal of -\frac{1}{15}.

$$\frac{7}{15}\left(-15\right)$$

Express \frac{7}{15}\left(-15\right) as a single fraction.

$$\frac{7\left(-15\right)}{15}$$

Multiply 7 and -15 to get -105.

$$\frac{-105}{15}$$

Divide -105 by 15 to get -7.

$$-7$$

Factor

$$-7$$