Solve (1/8*1)+(7/8(-1/4))

$$( \frac{ 1 }{ 8 } \times 1)+( \frac{ 7 }{ 8 } (- \frac{ 1 }{ 4 } ))$$

Evaluate

$$-\frac{3}{32}=-0.09375$$

Solution Steps

Multiply \frac{1}{8} and 1 to get \frac{1}{8}.

$$\frac{1}{8}+\frac{7}{8}\left(-\frac{1}{4}\right)$$

Multiply \frac{7}{8} times -\frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{8}+\frac{7\left(-1\right)}{8\times 4}$$

Do the multiplications in the fraction \frac{7\left(-1\right)}{8\times 4}.

$$\frac{1}{8}+\frac{-7}{32}$$

Fraction \frac{-7}{32} can be rewritten as -\frac{7}{32} by extracting the negative sign.

$$\frac{1}{8}-\frac{7}{32}$$

Least common multiple of 8 and 32 is 32. Convert \frac{1}{8} and \frac{7}{32} to fractions with denominator 32.

$$\frac{4}{32}-\frac{7}{32}$$

Since \frac{4}{32} and \frac{7}{32} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-7}{32}$$

Subtract 7 from 4 to get -3.

$$-\frac{3}{32}$$

Factor

$$-\frac{3}{32} = -0.09375$$