Solve (1/10)+(sqrt{256})*2*25

$$( \frac{ 1 }{ 10 } )+( \sqrt{ 256 } ) \times 2 \times 25$$

Evaluate

$$\frac{8001}{10}=800.1$$

Solution Steps

Multiply 2 and 25 to get 50.

$$\frac{1}{10}+50\sqrt{256}$$

Calculate the square root of 256 and get 16.

$$\frac{1}{10}+50\times 16$$

Multiply 50 and 16 to get 800.

$$\frac{1}{10}+800$$

Convert 800 to fraction \frac{8000}{10}.

$$\frac{1}{10}+\frac{8000}{10}$$

Since \frac{1}{10} and \frac{8000}{10} have the same denominator, add them by adding their numerators.

$$\frac{1+8000}{10}$$

Add 1 and 8000 to get 8001.

$$\frac{8001}{10}$$

Factor

$$\frac{3 ^ {2} \cdot 7 \cdot 127}{2 \cdot 5} = 800\frac{1}{10} = 800.1$$