Solve (1/1+1/2+1/4)-1

$$( \frac{ 1 }{ 1 } + \frac{ 1 }{ 2 } + \frac{ 1 }{ 4 } )-1$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Divide 1 by 1 to get 1.

$$1+\frac{1}{2}+\frac{1}{4}-1$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{2}{2}+\frac{1}{2}+\frac{1}{4}-1$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{2+1}{2}+\frac{1}{4}-1$$

Add 2 and 1 to get 3.

$$\frac{3}{2}+\frac{1}{4}-1$$

Least common multiple of 2 and 4 is 4. Convert \frac{3}{2} and \frac{1}{4} to fractions with denominator 4.

$$\frac{6}{4}+\frac{1}{4}-1$$

Since \frac{6}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{6+1}{4}-1$$

Add 6 and 1 to get 7.

$$\frac{7}{4}-1$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{7}{4}-\frac{4}{4}$$

Since \frac{7}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-4}{4}$$

Subtract 4 from 7 to get 3.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$