Solve (3^-2/4^-3)*(4/3)

$$( \frac{ { 3 }^{ -2 } }{ { 4 }^{ -3 } } ) \times ( \frac{ 4 }{ 3 } )$$

Evaluate

$$\frac{256}{27}\approx 9.481481481$$

Solution Steps

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$\frac{\frac{1}{9}}{4^{-3}}\times \frac{4}{3}$$

Calculate 4 to the power of -3 and get \frac{1}{64}.

$$\frac{\frac{1}{9}}{\frac{1}{64}}\times \frac{4}{3}$$

Divide \frac{1}{9} by \frac{1}{64} by multiplying \frac{1}{9} by the reciprocal of \frac{1}{64}.

$$\frac{1}{9}\times 64\times \frac{4}{3}$$

Multiply \frac{1}{9} and 64 to get \frac{64}{9}.

$$\frac{64}{9}\times \frac{4}{3}$$

Multiply \frac{64}{9} and \frac{4}{3} to get \frac{256}{27}.

$$\frac{256}{27}$$

Factor

$$\frac{2 ^ {8}}{3 ^ {3}} = 9\frac{13}{27} = 9.481481481481481$$