Solve (1^3/3-1)-((-1)3/3-1)=

$$( \frac{ { 1 }^{ 3 } }{ 3 } -1)-( \frac{ (-1)3 }{ 3 } -1)=$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$\frac{1}{3}-1-\left(\frac{-3}{3}-1\right)$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{1}{3}-\frac{3}{3}-\left(\frac{-3}{3}-1\right)$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-3}{3}-\left(\frac{-3}{3}-1\right)$$

Subtract 3 from 1 to get -2.

$$-\frac{2}{3}-\left(\frac{-3}{3}-1\right)$$

Cancel out 3 and 3.

$$-\frac{2}{3}-\left(-1-1\right)$$

Subtract 1 from -1 to get -2.

$$-\frac{2}{3}-\left(-2\right)$$

The opposite of -2 is 2.

$$-\frac{2}{3}+2$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{2}{3}+\frac{6}{3}$$

Since -\frac{2}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{-2+6}{3}$$

Add -2 and 6 to get 4.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$