Solve (x2/25)+(yz/9)=1

$$( \frac { x 2 } { 25 } ) + ( \frac { y z } { 9 } ) = 1$$

Solve for y (complex solution)

$$\left\{\begin{matrix}y=-\frac{9\left(x_{2}-25\right)}{25z}\text{, }&z\neq 0\\y\in \mathrm{C}\text{, }&x_{2}=25\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 225, the least common multiple of 25,9.

$$9x_{2}+25yz=225$$

Subtract 9x_{2} from both sides.

$$25yz=225-9x_{2}$$

The equation is in standard form.

$$25zy=225-9x_{2}$$

Divide both sides by 25z.

$$\frac{25zy}{25z}=\frac{225-9x_{2}}{25z}$$

Dividing by 25z undoes the multiplication by 25z.

$$y=\frac{225-9x_{2}}{25z}$$

Divide 225-9x_{2} by 25z.

$$y=\frac{9\left(25-x_{2}\right)}{25z}$$

Solve for x_2

$$x_{2}=-\frac{25yz}{9}+25$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 225, the least common multiple of 25,9.

$$9x_{2}+25yz=225$$

Subtract 25yz from both sides.

$$9x_{2}=225-25yz$$

Divide both sides by 9.

$$\frac{9x_{2}}{9}=\frac{225-25yz}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$x_{2}=\frac{225-25yz}{9}$$

Divide 225-25yz by 9.

$$x_{2}=-\frac{25yz}{9}+25$$

Solve for y

$$\left\{\begin{matrix}y=-\frac{9\left(x_{2}-25\right)}{25z}\text{, }&z\neq 0\\y\in \mathrm{R}\text{, }&x_{2}=25\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 225, the least common multiple of 25,9.

$$9x_{2}+25yz=225$$

Subtract 9x_{2} from both sides.

$$25yz=225-9x_{2}$$

The equation is in standard form.

$$25zy=225-9x_{2}$$

Divide both sides by 25z.

$$\frac{25zy}{25z}=\frac{225-9x_{2}}{25z}$$

Dividing by 25z undoes the multiplication by 25z.

$$y=\frac{225-9x_{2}}{25z}$$

Divide 225-9x_{2} by 25z.

$$y=\frac{9\left(25-x_{2}\right)}{25z}$$