Solve (x/39)^2=95/65

$$( \frac { x } { 39 } ) ^ { 2 } = \frac { 95 } { 65 }$$

Solve for x

$$x=3\sqrt{247}\approx 47.148700937$$

$$x=-3\sqrt{247}\approx -47.148700937$$

Steps by Finding Square Root

To raise \frac{x}{39} to a power, raise both numerator and denominator to the power and then divide.

$$\frac{x^{2}}{39^{2}}=\frac{95}{65}$$

Reduce the fraction \frac{95}{65} to lowest terms by extracting and canceling out 5.

$$\frac{x^{2}}{39^{2}}=\frac{19}{13}$$

Calculate 39 to the power of 2 and get 1521.

$$\frac{x^{2}}{1521}=\frac{19}{13}$$

Multiply both sides by 1521.

$$x^{2}=\frac{19}{13}\times 1521$$

Multiply \frac{19}{13} and 1521 to get 2223.

$$x^{2}=2223$$

Take the square root of both sides of the equation.

$$x=3\sqrt{247} x=-3\sqrt{247}$$