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\frac{\frac{\left(x+6\right)\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{\left(x-6\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+1 and x-1 is \left(x-1\right)\left(x+1\right). Multiply \frac{x+6}{x+1} times \frac{x-1}{x-1}. Multiply \frac{x-6}{x-1} times \frac{x+1}{x+1}.
\frac{\frac{\left(x+6\right)\left(x-1\right)-\left(x-6\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
Since \frac{\left(x+6\right)\left(x-1\right)}{\left(x-1\right)\left(x+1\right)} and \frac{\left(x-6\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{x^{2}-x+6x-6-x^{2}-x+6x+6}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
Do the multiplications in \left(x+6\right)\left(x-1\right)-\left(x-6\right)\left(x+1\right).
\frac{\frac{10x}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
Combine like terms in x^{2}-x+6x-6-x^{2}-x+6x+6.
\frac{10x\left(x^{2}-2x+1\right)}{\left(x-1\right)\left(x+1\right)\times 5x}
Divide \frac{10x}{\left(x-1\right)\left(x+1\right)} by \frac{5x}{x^{2}-2x+1} by multiplying \frac{10x}{\left(x-1\right)\left(x+1\right)} by the reciprocal of \frac{5x}{x^{2}-2x+1}.
\frac{2\left(x^{2}-2x+1\right)}{\left(x-1\right)\left(x+1\right)}
Cancel out 5x in both numerator and denominator.
\frac{2\left(x-1\right)^{2}}{\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored.
\frac{2\left(x-1\right)}{x+1}
Cancel out x-1 in both numerator and denominator.
\frac{2x-2}{x+1}
Expand the expression.
\frac{\frac{\left(x+6\right)\left(x-1\right)}{\left(x-1\right)\left(x+1\right)}-\frac{\left(x-6\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+1 and x-1 is \left(x-1\right)\left(x+1\right). Multiply \frac{x+6}{x+1} times \frac{x-1}{x-1}. Multiply \frac{x-6}{x-1} times \frac{x+1}{x+1}.
\frac{\frac{\left(x+6\right)\left(x-1\right)-\left(x-6\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
Since \frac{\left(x+6\right)\left(x-1\right)}{\left(x-1\right)\left(x+1\right)} and \frac{\left(x-6\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{x^{2}-x+6x-6-x^{2}-x+6x+6}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
Do the multiplications in \left(x+6\right)\left(x-1\right)-\left(x-6\right)\left(x+1\right).
\frac{\frac{10x}{\left(x-1\right)\left(x+1\right)}}{\frac{5x}{x^{2}-2x+1}}
Combine like terms in x^{2}-x+6x-6-x^{2}-x+6x+6.
\frac{10x\left(x^{2}-2x+1\right)}{\left(x-1\right)\left(x+1\right)\times 5x}
Divide \frac{10x}{\left(x-1\right)\left(x+1\right)} by \frac{5x}{x^{2}-2x+1} by multiplying \frac{10x}{\left(x-1\right)\left(x+1\right)} by the reciprocal of \frac{5x}{x^{2}-2x+1}.
\frac{2\left(x^{2}-2x+1\right)}{\left(x-1\right)\left(x+1\right)}
Cancel out 5x in both numerator and denominator.
\frac{2\left(x-1\right)^{2}}{\left(x-1\right)\left(x+1\right)}
Factor the expressions that are not already factored.
\frac{2\left(x-1\right)}{x+1}
Cancel out x-1 in both numerator and denominator.
\frac{2x-2}{x+1}
Expand the expression.