Solve (k+1/2)*2=2+v*(-3)

$$( \frac { k + 1 } { 2 } ) \cdot 2 = 2 + v \cdot ( - 3 )$$

Solve for k

$$k=1-3v$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$\left(k+1\right)\times 2=4+2v\left(-3\right)$$

Use the distributive property to multiply k+1 by 2.

$$2k+2=4+2v\left(-3\right)$$

Multiply 2 and -3 to get -6.

$$2k+2=4-6v$$

Subtract 2 from both sides.

$$2k=4-6v-2$$

Subtract 2 from 4 to get 2.

$$2k=2-6v$$

Divide both sides by 2.

$$\frac{2k}{2}=\frac{2-6v}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$k=\frac{2-6v}{2}$$

Divide 2-6v by 2.

$$k=1-3v$$

Solve for v

$$v=\frac{1-k}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$\left(k+1\right)\times 2=4+2v\left(-3\right)$$

Use the distributive property to multiply k+1 by 2.

$$2k+2=4+2v\left(-3\right)$$

Multiply 2 and -3 to get -6.

$$2k+2=4-6v$$

Swap sides so that all variable terms are on the left hand side.

$$4-6v=2k+2$$

Subtract 4 from both sides.

$$-6v=2k+2-4$$

Subtract 4 from 2 to get -2.

$$-6v=2k-2$$

Divide both sides by -6.

$$\frac{-6v}{-6}=\frac{2k-2}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$v=\frac{2k-2}{-6}$$

Divide -2+2k by -6.

$$v=\frac{1-k}{3}$$