Skip to main content
Factor
Tick mark Image
Evaluate
Tick mark Image
Graph

Similar Problems from Web Search

Share

\frac{\left(e^{x}+\frac{1}{e^{x}}\right)^{2}-\left(e^{x}-\frac{1}{e^{x}}\right)^{2}}{4}
Factor out \frac{1}{4}.
\left(e^{x}+\frac{1}{e^{x}}-\left(e^{x}-\frac{1}{e^{x}}\right)\right)\left(e^{x}+\frac{1}{e^{x}}+e^{x}-\frac{1}{e^{x}}\right)
Consider \left(e^{x}+\left(e^{x}\right)^{-1}\right)^{2}-\left(e^{x}-\left(e^{x}\right)^{-1}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(e^{x}+\frac{1}{e^{x}}-\left(e^{x}-\frac{1}{e^{x}}\right)\right)\left(e^{x}+\frac{1}{e^{x}}+e^{x}-\frac{1}{e^{x}}\right)}{4}
Rewrite the complete factored expression.