Solve (9h/2)div3=ah/2

$$( \frac { 9 h } { 2 } ) \div 3 = \frac { a h } { 2 }$$

Solve for a

$$\left\{\begin{matrix}\\a=3\text{, }&\text{unconditionally}\\a\in \mathrm{R}\text{, }&h=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 3,2.

$$2\times \frac{9h}{2}=3ah$$

Express 2\times \frac{9h}{2} as a single fraction.

$$\frac{2\times 9h}{2}=3ah$$

Cancel out 2 and 2.

$$9h=3ah$$

Swap sides so that all variable terms are on the left hand side.

$$3ah=9h$$

The equation is in standard form.

$$3ha=9h$$

Divide both sides by 3h.

$$\frac{3ha}{3h}=\frac{9h}{3h}$$

Dividing by 3h undoes the multiplication by 3h.

$$a=\frac{9h}{3h}$$

Divide 9h by 3h.

$$a=3$$

Solve for h

$$\left\{\begin{matrix}\\h=0\text{, }&\text{unconditionally}\\h\in \mathrm{R}\text{, }&a=3\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 3,2.

$$2\times \frac{9h}{2}=3ah$$

Express 2\times \frac{9h}{2} as a single fraction.

$$\frac{2\times 9h}{2}=3ah$$

Cancel out 2 and 2.

$$9h=3ah$$

Subtract 3ah from both sides.

$$9h-3ah=0$$

Combine all terms containing h.

$$\left(9-3a\right)h=0$$

Divide 0 by 9-3a.

$$h=0$$