Solve (9/4)^2-2*9/4-3

$$( \frac { 9 } { 4 } ) ^ { 2 } - 2 \times \frac { 9 } { 4 } - 3$$

Evaluate

$$-\frac{39}{16}=-2.4375$$

Solution Steps

Calculate \frac{9}{4} to the power of 2 and get \frac{81}{16}.

$$\frac{81}{16}-2\times \frac{9}{4}-3$$

Express 2\times \frac{9}{4} as a single fraction.

$$\frac{81}{16}-\frac{2\times 9}{4}-3$$

Multiply 2 and 9 to get 18.

$$\frac{81}{16}-\frac{18}{4}-3$$

Reduce the fraction \frac{18}{4} to lowest terms by extracting and canceling out 2.

$$\frac{81}{16}-\frac{9}{2}-3$$

Least common multiple of 16 and 2 is 16. Convert \frac{81}{16} and \frac{9}{2} to fractions with denominator 16.

$$\frac{81}{16}-\frac{72}{16}-3$$

Since \frac{81}{16} and \frac{72}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{81-72}{16}-3$$

Subtract 72 from 81 to get 9.

$$\frac{9}{16}-3$$

Convert 3 to fraction \frac{48}{16}.

$$\frac{9}{16}-\frac{48}{16}$$

Since \frac{9}{16} and \frac{48}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-48}{16}$$

Subtract 48 from 9 to get -39.

$$-\frac{39}{16}$$

Factor

$$-\frac{39}{16} = -2\frac{7}{16} = -2.4375$$