Solve (9/2x-3/4y+1=0)

$$( \frac { 9 } { 2 } x - \frac { 3 } { 4 } y + 1 = 0 )$$

Solve for x

$$x=\frac{y}{6}-\frac{2}{9}$$

Steps for Solving Linear Equation

Add \frac{3}{4}y to both sides. Anything plus zero gives itself.

$$\frac{9}{2}x+1=\frac{3}{4}y$$

Subtract 1 from both sides.

$$\frac{9}{2}x=\frac{3}{4}y-1$$

The equation is in standard form.

$$\frac{9}{2}x=\frac{3y}{4}-1$$

Divide both sides of the equation by \frac{9}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{9}{2}x}{\frac{9}{2}}=\frac{\frac{3y}{4}-1}{\frac{9}{2}}$$

Dividing by \frac{9}{2} undoes the multiplication by \frac{9}{2}.

$$x=\frac{\frac{3y}{4}-1}{\frac{9}{2}}$$

Divide \frac{3y}{4}-1 by \frac{9}{2} by multiplying \frac{3y}{4}-1 by the reciprocal of \frac{9}{2}.

$$x=\frac{y}{6}-\frac{2}{9}$$

Solve for y

$$y=6x+\frac{4}{3}$$

Steps for Solving Linear Equation

Subtract \frac{9}{2}x from both sides. Anything subtracted from zero gives its negation.

$$-\frac{3}{4}y+1=-\frac{9}{2}x$$

Subtract 1 from both sides.

$$-\frac{3}{4}y=-\frac{9}{2}x-1$$

The equation is in standard form.

$$-\frac{3}{4}y=-\frac{9x}{2}-1$$

Divide both sides of the equation by -\frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{4}y}{-\frac{3}{4}}=\frac{-\frac{9x}{2}-1}{-\frac{3}{4}}$$

Dividing by -\frac{3}{4} undoes the multiplication by -\frac{3}{4}.

$$y=\frac{-\frac{9x}{2}-1}{-\frac{3}{4}}$$

Divide -\frac{9x}{2}-1 by -\frac{3}{4} by multiplying -\frac{9x}{2}-1 by the reciprocal of -\frac{3}{4}.

$$y=6x+\frac{4}{3}$$