Solve (8/5-1/1)*5/27

$$( \frac { 8 } { 5 } - \frac { 1 } { 1 } ) \cdot \frac { 5 } { 27 }$$

Evaluate

$$\frac{1}{9}\approx 0.111111111$$

Solution Steps

Divide 1 by 1 to get 1.

$$\left(\frac{8}{5}-1\right)\times \frac{5}{27}$$

Convert 1 to fraction \frac{5}{5}.

$$\left(\frac{8}{5}-\frac{5}{5}\right)\times \frac{5}{27}$$

Since \frac{8}{5} and \frac{5}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-5}{5}\times \frac{5}{27}$$

Subtract 5 from 8 to get 3.

$$\frac{3}{5}\times \frac{5}{27}$$

Multiply \frac{3}{5} times \frac{5}{27} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 5}{5\times 27}$$

Cancel out 5 in both numerator and denominator.

$$\frac{3}{27}$$

Reduce the fraction \frac{3}{27} to lowest terms by extracting and canceling out 3.

$$\frac{1}{9}$$

Factor

$$\frac{1}{3 ^ {2}} = 0.1111111111111111$$