Solve (8/5*31/3)+(63/7:4,5)

$$( \frac { 8 } { 5 } \times 3 \frac { 1 } { 3 } ) + ( 6 \frac { 3 } { 7 } : 4,5 )$$

Evaluate

$$\frac{142}{21}\approx 6,761904762$$

Solution Steps

Multiply 3 and 3 to get 9.

$$\frac{8}{5}\times \frac{9+1}{3}+\frac{\frac{6\times 7+3}{7}}{4,5}$$

Add 9 and 1 to get 10.

$$\frac{8}{5}\times \frac{10}{3}+\frac{\frac{6\times 7+3}{7}}{4,5}$$

Multiply \frac{8}{5} times \frac{10}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 10}{5\times 3}+\frac{\frac{6\times 7+3}{7}}{4,5}$$

Do the multiplications in the fraction \frac{8\times 10}{5\times 3}.

$$\frac{80}{15}+\frac{\frac{6\times 7+3}{7}}{4,5}$$

Reduce the fraction \frac{80}{15} to lowest terms by extracting and canceling out 5.

$$\frac{16}{3}+\frac{\frac{6\times 7+3}{7}}{4,5}$$

Express \frac{\frac{6\times 7+3}{7}}{4,5} as a single fraction.

$$\frac{16}{3}+\frac{6\times 7+3}{7\times 4,5}$$

Multiply 6 and 7 to get 42.

$$\frac{16}{3}+\frac{42+3}{7\times 4,5}$$

Add 42 and 3 to get 45.

$$\frac{16}{3}+\frac{45}{7\times 4,5}$$

Multiply 7 and 4,5 to get 31,5.

$$\frac{16}{3}+\frac{45}{31,5}$$

Expand \frac{45}{31,5} by multiplying both numerator and the denominator by 10.

$$\frac{16}{3}+\frac{450}{315}$$

Reduce the fraction \frac{450}{315} to lowest terms by extracting and canceling out 45.

$$\frac{16}{3}+\frac{10}{7}$$

Least common multiple of 3 and 7 is 21. Convert \frac{16}{3} and \frac{10}{7} to fractions with denominator 21.

$$\frac{112}{21}+\frac{30}{21}$$

Since \frac{112}{21} and \frac{30}{21} have the same denominator, add them by adding their numerators.

$$\frac{112+30}{21}$$

Add 112 and 30 to get 142.

$$\frac{142}{21}$$

Factor

$$\frac{2 \cdot 71}{3 \cdot 7} = 6\frac{16}{21} = 6.761904761904762$$