Solve (8/3x^3-5/17x^2-9x-2/34)+(7/6x^3+frac{3}{34}x^2+frac{5}{17}

$$( \frac { 8 } { 3 } x ^ { 3 } - \frac { 5 } { 17 } x ^ { 2 } - 9 x - \frac { 2 } { 34 } ) + ( \frac { 7 } { 6 } x ^ { 3 } + \frac { 3 } { 34 } x ^ { 2 } + \frac { 5 } { 17 }$$

Evaluate

$$\frac{23x^{3}}{6}-\frac{7x^{2}}{34}-9x+\frac{4}{17}$$

Solution Steps

Reduce the fraction \frac{2}{34} to lowest terms by extracting and canceling out 2.

$$\frac{8}{3}x^{3}-\frac{5}{17}x^{2}-9x-\frac{1}{17}+\frac{7}{6}x^{3}+\frac{3}{34}x^{2}+\frac{5}{17}$$

Combine \frac{8}{3}x^{3} and \frac{7}{6}x^{3} to get \frac{23}{6}x^{3}.

$$\frac{23}{6}x^{3}-\frac{5}{17}x^{2}-9x-\frac{1}{17}+\frac{3}{34}x^{2}+\frac{5}{17}$$

Combine -\frac{5}{17}x^{2} and \frac{3}{34}x^{2} to get -\frac{7}{34}x^{2}.

$$\frac{23}{6}x^{3}-\frac{7}{34}x^{2}-9x-\frac{1}{17}+\frac{5}{17}$$

Add -\frac{1}{17} and \frac{5}{17} to get \frac{4}{17}.

$$\frac{23}{6}x^{3}-\frac{7}{34}x^{2}-9x+\frac{4}{17}$$

Factor

$$\frac{391x^{3}-21x^{2}-918x+24}{102}$$

Solution Steps

Factor out \frac{1}{102}. Polynomial 391x^{3}-21x^{2}-918x+24 is not factored since it does not have any rational roots.

$$\frac{391x^{3}-21x^{2}-918x+24}{102}$$