Solve (8/3*3-075*1/6)*1/3-9=

$$( \frac { 8 } { 3 } \cdot 3 - 075 \cdot \frac { 1 } { 6 } ) \cdot \frac { 1 } { 3 } - 9 =$$

Evaluate

$$-\frac{19}{3}\approx -6.333333333$$

Solution Steps

Cancel out 3 and 3.

$$\left(8-0\times 75\times \frac{1}{6}\right)\times \frac{1}{3}-9$$

Multiply 0 and 75 to get 0.

$$\left(8-0\times \frac{1}{6}\right)\times \frac{1}{3}-9$$

Multiply 0 and \frac{1}{6} to get 0.

$$\left(8-0\right)\times \frac{1}{3}-9$$

Subtract 0 from 8 to get 8.

$$8\times \frac{1}{3}-9$$

Multiply 8 and \frac{1}{3} to get \frac{8}{3}.

$$\frac{8}{3}-9$$

Convert 9 to fraction \frac{27}{3}.

$$\frac{8}{3}-\frac{27}{3}$$

Since \frac{8}{3} and \frac{27}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-27}{3}$$

Subtract 27 from 8 to get -19.

$$-\frac{19}{3}$$

Factor

$$-\frac{19}{3} = -6\frac{1}{3} = -6.333333333333333$$