Solve (8/3*3-0,75*1/6)*1/3-9=

$$( \frac { 8 } { 3 } \cdot 3 - 0,75 \cdot \frac { 1 } { 6 } ) \cdot \frac { 1 } { 3 } - 9 =$$

Evaluate

$$-6,375$$

Solution Steps

Cancel out 3 and 3.

$$\left(8-0,75\times \frac{1}{6}\right)\times \frac{1}{3}-9$$

Convert decimal number 0,75 to fraction \frac{75}{100}. Reduce the fraction \frac{75}{100} to lowest terms by extracting and canceling out 25.

$$\left(8-\frac{3}{4}\times \frac{1}{6}\right)\times \frac{1}{3}-9$$

Multiply \frac{3}{4} times \frac{1}{6} by multiplying numerator times numerator and denominator times denominator.

$$\left(8-\frac{3\times 1}{4\times 6}\right)\times \frac{1}{3}-9$$

Do the multiplications in the fraction \frac{3\times 1}{4\times 6}.

$$\left(8-\frac{3}{24}\right)\times \frac{1}{3}-9$$

Reduce the fraction \frac{3}{24} to lowest terms by extracting and canceling out 3.

$$\left(8-\frac{1}{8}\right)\times \frac{1}{3}-9$$

Convert 8 to fraction \frac{64}{8}.

$$\left(\frac{64}{8}-\frac{1}{8}\right)\times \frac{1}{3}-9$$

Since \frac{64}{8} and \frac{1}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{64-1}{8}\times \frac{1}{3}-9$$

Subtract 1 from 64 to get 63.

$$\frac{63}{8}\times \frac{1}{3}-9$$

Multiply \frac{63}{8} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{63\times 1}{8\times 3}-9$$

Do the multiplications in the fraction \frac{63\times 1}{8\times 3}.

$$\frac{63}{24}-9$$

Reduce the fraction \frac{63}{24} to lowest terms by extracting and canceling out 3.

$$\frac{21}{8}-9$$

Convert 9 to fraction \frac{72}{8}.

$$\frac{21}{8}-\frac{72}{8}$$

Since \frac{21}{8} and \frac{72}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-72}{8}$$

Subtract 72 from 21 to get -51.

$$-\frac{51}{8}$$

Factor

$$-6,375$$