Solve (7/8+025-1/3)div1/11

$$( \frac { 7 } { 8 } + 025 - \frac { 1 } { 3 } ) \div \frac { 1 } { 11 }$$

Evaluate

$$\frac{143}{24}\approx 5.958333333$$

Solution Steps

Multiply 0 and 25 to get 0.

$$\frac{\frac{7}{8}+0-\frac{1}{3}}{\frac{1}{11}}$$

Add \frac{7}{8} and 0 to get \frac{7}{8}.

$$\frac{\frac{7}{8}-\frac{1}{3}}{\frac{1}{11}}$$

Least common multiple of 8 and 3 is 24. Convert \frac{7}{8} and \frac{1}{3} to fractions with denominator 24.

$$\frac{\frac{21}{24}-\frac{8}{24}}{\frac{1}{11}}$$

Since \frac{21}{24} and \frac{8}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{21-8}{24}}{\frac{1}{11}}$$

Subtract 8 from 21 to get 13.

$$\frac{\frac{13}{24}}{\frac{1}{11}}$$

Divide \frac{13}{24} by \frac{1}{11} by multiplying \frac{13}{24} by the reciprocal of \frac{1}{11}.

$$\frac{13}{24}\times 11$$

Express \frac{13}{24}\times 11 as a single fraction.

$$\frac{13\times 11}{24}$$

Multiply 13 and 11 to get 143.

$$\frac{143}{24}$$

Factor

$$\frac{11 \cdot 13}{2 ^ {3} \cdot 3} = 5\frac{23}{24} = 5.958333333333333$$