Solve (7/8+5/3)*2/8

$$( \frac { 7 } { 8 } + \frac { 5 } { 3 } ) \cdot \frac { 2 } { 8 }$$

Evaluate

$$\frac{61}{96}\approx 0.635416667$$

Solution Steps

Least common multiple of 8 and 3 is 24. Convert \frac{7}{8} and \frac{5}{3} to fractions with denominator 24.

$$\left(\frac{21}{24}+\frac{40}{24}\right)\times \frac{2}{8}$$

Since \frac{21}{24} and \frac{40}{24} have the same denominator, add them by adding their numerators.

$$\frac{21+40}{24}\times \frac{2}{8}$$

Add 21 and 40 to get 61.

$$\frac{61}{24}\times \frac{2}{8}$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{61}{24}\times \frac{1}{4}$$

Multiply \frac{61}{24} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{61\times 1}{24\times 4}$$

Do the multiplications in the fraction \frac{61\times 1}{24\times 4}.

$$\frac{61}{96}$$

Factor

$$\frac{61}{2 ^ {5} \cdot 3} = 0.6354166666666666$$