Solve (7/4-5/6)*(4+4/11)=

$$( \frac { 7 } { 4 } - \frac { 5 } { 6 } ) \cdot ( 4 + \frac { 4 } { 11 } ) =$$

Evaluate

$$4$$

Solution Steps

Least common multiple of 4 and 6 is 12. Convert \frac{7}{4} and \frac{5}{6} to fractions with denominator 12.

$$\left(\frac{21}{12}-\frac{10}{12}\right)\left(4+\frac{4}{11}\right)$$

Since \frac{21}{12} and \frac{10}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-10}{12}\left(4+\frac{4}{11}\right)$$

Subtract 10 from 21 to get 11.

$$\frac{11}{12}\left(4+\frac{4}{11}\right)$$

Convert 4 to fraction \frac{44}{11}.

$$\frac{11}{12}\left(\frac{44}{11}+\frac{4}{11}\right)$$

Since \frac{44}{11} and \frac{4}{11} have the same denominator, add them by adding their numerators.

$$\frac{11}{12}\times \frac{44+4}{11}$$

Add 44 and 4 to get 48.

$$\frac{11}{12}\times \frac{48}{11}$$

Multiply \frac{11}{12} times \frac{48}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{11\times 48}{12\times 11}$$

Cancel out 11 in both numerator and denominator.

$$\frac{48}{12}$$

Divide 48 by 12 to get 4.

$$4$$

Factor

$$2^{2}$$