Solve (frac{6f^{2}g^{-8}h^2}{32fg^-5h^4})^0

$$( \frac { 6 f ^ { 2 } g ^ { - 8 } h ^ { 2 } } { 32 f g ^ { - 5 } h ^ { 4 } } ) ^ { 0 }$$

Evaluate

$$1$$

Solution Steps

Cancel out 2fh^{2} in both numerator and denominator.

$$\left(\frac{3g^{-8}f}{16g^{-5}h^{2}}\right)^{0}$$

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$\left(\frac{3f}{16h^{2}g^{3}}\right)^{0}$$

Calculate \frac{3f}{16h^{2}g^{3}} to the power of 0 and get 1.

$$1$$

Factor

$$1$$