Solve (6/7)^-1*(6/7)^5*(7/6)^3=

$$( \frac { 6 } { 7 } ) ^ { - 1 } \cdot ( \frac { 6 } { 7 } ) ^ { 5 } \cdot ( \frac { 7 } { 6 } ) ^ { 3 } =$$

Evaluate

$$\frac{6}{7}\approx 0.857142857$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -1 and 5 to get 4.

$$\left(\frac{6}{7}\right)^{4}\times \left(\frac{7}{6}\right)^{3}$$

Calculate \frac{6}{7} to the power of 4 and get \frac{1296}{2401}.

$$\frac{1296}{2401}\times \left(\frac{7}{6}\right)^{3}$$

Calculate \frac{7}{6} to the power of 3 and get \frac{343}{216}.

$$\frac{1296}{2401}\times \frac{343}{216}$$

Multiply \frac{1296}{2401} and \frac{343}{216} to get \frac{6}{7}.

$$\frac{6}{7}$$

Factor

$$\frac{2 \cdot 3}{7} = 0.8571428571428571$$