Solve (6/4)^-3=(6/4)^3

$$( \frac { 6 } { 4 } ) ^ { - 3 } = ( \frac { 6 } { 4 } ) ^ { 3 }$$

Verify

Solution Steps

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\left(\frac{3}{2}\right)^{-3}=\left(\frac{6}{4}\right)^{3}$$

Calculate \frac{3}{2} to the power of -3 and get \frac{8}{27}.

$$\frac{8}{27}=\left(\frac{6}{4}\right)^{3}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{8}{27}=\left(\frac{3}{2}\right)^{3}$$

Calculate \frac{3}{2} to the power of 3 and get \frac{27}{8}.

$$\frac{8}{27}=\frac{27}{8}$$

Least common multiple of 27 and 8 is 216. Convert \frac{8}{27} and \frac{27}{8} to fractions with denominator 216.

$$\frac{64}{216}=\frac{729}{216}$$

Compare \frac{64}{216} and \frac{729}{216}.

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